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marishachu [46]
3 years ago
9

Consider the equation . how many different solutions does this equation have if all the variables must be positive integers? ent

er the exact numeric answer.
Mathematics
1 answer:
Schach [20]3 years ago
6 0
What is the equation?
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How do you learn pi? What is it used for? Please be specific when explaining.
Ugo [173]

Answer:

just memorize the numbers in pi, I know the first like 4 numbers. 3.1415

Step-by-step explanation:

it is used for calculating the area of circles.

4 0
2 years ago
An ice cream store sells cones for $0.90 and sundaes for $1.65. On a day when 148 cones and sundaes total were sold, the sales w
monitta

Answer:

Select the most appropriate translation to the following question.

Do you have a book?

¿Qué hizo?

¿Tiene Ud. un libro?

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¿Qué quiere decir "lapicero"?

Step-by-step explanation:

5 0
3 years ago
Maths worksheet help
MA_775_DIABLO [31]
                     math worksheet
1 x+2=4
2 x+3+x=7
3 find x                                                                 here it is -   x
7 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
F(x) = 4x^2 + 3x - 11<br> f(-3)
Mnenie [13.5K]
Just plus in x for -3
f(x) = 4(-3)^2 + 3(-3) - 11
f (x) = 4(9) -9 - 11
f(x) = 36 - 20
f(x) = 16
3 0
3 years ago
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