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Gala2k [10]
3 years ago
7

Please help me with some Algebra 2. Last stretch of the trimester and it’s 3:13AM. It’s my own fault for getting myself into thi

s situation but I just really need some assistance.

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

A. 23+(6-1)x-3

B. 93

Step-by-step explanation:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

            = 23 + (5) x -3

            = 23 + (-15)

            = 8 - number of boxes in the top row.

b) Sum = N/2[2F + (N - 1) x D]

            = 6/2[2*23 + (6 - 1) x -3]

             = 3  [46  +    (5) x -3 ]

             = 3  [46  +      -15 ]

             = 3  [ 31 ]

             = 93 - total number of boxes in the entire display.

Hope this helps! Its 3:25 AM for me too so I know how you feel.

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Destiny and Guadalupe are shopping. Destiny buys 2 pairs of pants and 6 bracelets and pays $178.Guadalupe buys 3 pairs of pants
ziro4ka [17]

For the entirety of this problem, p will represent a pair of pants and b will represent a bracelet.

Step 1) Set up equations for Destiny and Guadalupe

Destiny: 178 = 2p + 6b

Guadalupe: 155 = 3p + 2b

I will be using substitution to solve this problem, but elimination can also be used.

Step 2) Solve Destiny's equation for p

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178 - 6b = 2p

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Step 3) Substitute the found value of p from Destiny's equation into Guadalupe's equation and solve for b

155 = 3(89 - 3b) + 2b

155 = 267 - 9b + 2b

155 = 267 - 7b

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b = 16

Step 4) Use the value of b found in step 3, plug that back into our equation from step 2 and solve for p

89 - 3(16) = p

89 - 48 = p

p = 41

one pair of pants = $16

one bracelet = $41

Hope this helps!! :)

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