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Gala2k [10]
3 years ago
7

Please help me with some Algebra 2. Last stretch of the trimester and it’s 3:13AM. It’s my own fault for getting myself into thi

s situation but I just really need some assistance.

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

A. 23+(6-1)x-3

B. 93

Step-by-step explanation:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

            = 23 + (5) x -3

            = 23 + (-15)

            = 8 - number of boxes in the top row.

b) Sum = N/2[2F + (N - 1) x D]

            = 6/2[2*23 + (6 - 1) x -3]

             = 3  [46  +    (5) x -3 ]

             = 3  [46  +      -15 ]

             = 3  [ 31 ]

             = 93 - total number of boxes in the entire display.

Hope this helps! Its 3:25 AM for me too so I know how you feel.

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WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

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We have,

3x^2y^2-2xy^5

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