When you divide numbers, you make the value smaller. So subtract the exponents will make the value with that base smaller.
The answer is 1.02 according to calculations
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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The answer is c to my calculations.
Step-by-step explanation:
first fish tank: 95-4x
second fish tank: 40+5x
1. Define variable
The variable x represents the number of days.
2. Write the inequality
<em>95-4x=40+5x</em>
<em />
3. You probably don't need the answer but I am just going to solve.
The first fish tank will have less water than the second fish tank after 7 days.
<em>95-4x=40+5x </em>
<em>95-4(7)=40+5(7)</em>
<em>95-28=40+35</em>
<em>67=75</em>
<em>Since the first equation (95-4x) represents the first fish tank, and the second equation (40+5x) represents the second fish tank, the solution shows how the amount of water in the first fish tank is less than the amount of water un the second fish tank after 7 days.</em>
