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Leto [7]
3 years ago
14

A number y increased by 5 is at most 28​

Mathematics
2 answers:
White raven [17]3 years ago
5 0

The answer to your question is this:

Iteru [2.4K]3 years ago
4 0

y + 5\leq 28\\y\leq 23

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You are an assistant director of the alumni association at a local university. You attend a presentation given by the university
NNADVOKAT [17]

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

<h2> p1 -p2 ± z*\sqrt{((1-p1)*p1)/n1 + ((1-p2)*p2/n2}</h2>

0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = <u>0.102</u>

= 0.02 - 0.082 = <u>-0.062</u>

<u>There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>

<u></u>

<u>There is no significant difference between the two.</u>

5 0
3 years ago
Find the arc measures and angles listed below.
rusak2 [61]

Answer if you divide them or x them you'll get the answer!

4 0
2 years ago
1,1,4,3,9,6,16,10,25,15,
Butoxors [25]

what are we suppose to do in this?

6 0
3 years ago
PLEASE ANSWER QUICK!!!SHOW STEPS
Vedmedyk [2.9K]
5. Given the equation y = (1/4) cos[(2pi/3)*theta]:
5a. For the general equation y = a cos(bx), the period is given by 2pi/b. In this equation, b = 2pi/3, so this means that 2pi/b = 2pi/(2pi/3) = 3. Therefore, the period of this equation is 3, and the cosine wave repeats itself every 3 x-units.
5b. For the general equation y = a cos(bx), the amplitude is given by a. Therefore the amplitude is a = 1/4, and this means that the cosine wave's range is from -1/4 to 1/4 for all values of x.
5c. The equation of the midline is y = 0. This represents the average value over the wave. This is determined by adding the highest and lowest values of the range and taking the average, in this case, 1/4 + (-1/4) = 0, and 0 / 2 = 0. Another way to do this is using the general equation y = a cos(bx) + c, where the midline's equation is y = c. In this case, there is no value of c in the given, implying that c = 0, and the midline is y = 0.

6. Let the horizontal distance be x. Then tan42 = h/x, and h = x tan42. Then using the Pythagorean theorem: 3280^2 = h^2 + x^2
3280^2 = x^2 (tan42)^2 + x^2
3280^2 = x^2 [(tan42)^2 + 1]
x = 2437.52
Therefore, h = x tan42 = 2,194.75 ft.

5 0
3 years ago
Read 2 more answers
Find the area of a circle with a diameter of 16.
mylen [45]

Answer:

A = 64 pi

or approximately 200.96

Step-by-step explanation:

The diameter is twice the radius

d = 2r

16 = 2r

Divide by 2

16/2 = 2r/2

8 =r

The area of a circle is

A = pi *r^2

A = pi*(8)^2

   = pi *64

Or if we approximate pi as 3.14

A = (3.14) * (64)

A = 200.96

8 0
3 years ago
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