Consider the line y = 7x-1.
What is the slope of a line
parallel to this line?
What is the slope of a line
perpendicular to this line?
Answer:
10
Step-by-step explanation:
=2.5(6*4)/6
=2.5*4(6 and 6 gets cancel)
=10
Answer:83÷3=27.6 or 27.667
Step-by-step explanation:
Answer:
- x ≥ 2009
- 3.2x -6222.8
- 257.2 mm
- year 2100
Step-by-step explanation:
1. The problem statement tells you the function applies for year values (x) 2009 and later. The domain is real numbers greater than or equal to 2009.
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2. We can use the distributive property to eliminate parentheses:
3.2(x -2009) +206 = 3.2x -6428.8 +206
= 3.2x -6222.8
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3. Put 2025 in the equation and do the arithmetic
g(2025) = 3.2·2025 -6222.8 = 257.2 . . . . mm
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4. Put this value of level rise in the equation and solve for x.
g(x) = 3.2x -6222.8
500 = 3.2x -6222.8 . . put 500 mm where g(x) is in the equation
6722.8 = 3.2x . . . . . . . add 6222.8
x = 6722.8/3.2 = 2100.875
The water rise will be equal to about half a meter late in the year 2100.
KL + JK = 27
6x + 3x = 27
9x = 27
x = 27/9
x = 3
KL = 6x
KL = 6 × 3
KL = 18
