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notka56 [123]
4 years ago
9

6/21 turned into a decimal

Mathematics
1 answer:
Ymorist [56]4 years ago
3 0
6.21 i think or 0.621
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What is the value of x in the equation 5(3x + 4) = 23?
Marina86 [1]
Fraction form: 1/5

Decimal form: 0.2



First, distribute the 5 to the (3x + 4).

15x + 20 = 23

Subtract 20 from both sides.

15x = 3

Now divide by 15 on both sides.

x = 1/5

Keep in mind 1/5 is also 0.2 in decimal form.

There’s the answer.



Please consider marking this answer as Brainliest to help me advance.
3 0
3 years ago
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For which set of probabilities would events A and B be independent?
Basile [38]
The answer is a because set of probalitie
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Find value of x<br> (2x+7)=(3x-52)
Gnoma [55]

Step 1: Subtract 3x from both sides.
−x+7=−52

Step 2: Subtract 7 from both sides.<span><span><span><span>
−x</span>+7</span>−7</span>=<span><span>−52</span>−7</span></span><span><span>
−x</span>=<span>−59</span></span>
Step 3: Divide both sides by -1.<span><span><span>‌
<span><span>−x</span><span>−1</span></span></span>‌</span>=<span><span>‌<span><span>−59</span><span>−1</span></span></span>‌</span></span><span>
x=59</span>
8 0
3 years ago
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PLEASE ANSWER HURRY THANK YOU
Juliette [100K]

Answer:  A. \dfrac{6}{203}

Step-by-step explanation:

Given : Jason bought 10 of the 30 raffle tickets for a drawing.

i.e. Total tickets = 30

Also, Number of prizes = 3

The total number of combinations of getting 3 prizes out of 30 tickets = ^{30}C_3

The number of combinations of getting 3 prizes out of 10 tickets =^{10}C_3

Then, the probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away will be :

\dfrac{{^{30}C_3}}{^{10}C_3}

=\dfrac{\dfrac{10!}{3!7!}}{\dfrac{30!}{3!27!}}=\dfrac{120}{4060}=\dfrac{6}{203}

Hence, the probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away is \dfrac{6}{203} .

Hence, the correct answer is A. 6/203.

3 0
3 years ago
Read 2 more answers
6x2 + 5x + 1<br>how do I factor this out? ​
Oduvanchick [21]

Answer:

(3x + 1) (2x + 1)

Step-by-step explanation:

ax² + bx + c can be factored using the AC method:

1. Multiply a and c.

2. Find factors of ac that add up to b.

3. Divide each factor by a; reduce the fractions.

4. The denominator is the coefficient, the numerator is the constant.

6x² + 5x + 1

1. ac = 6 × 1 = 6

2. Factors of 6 that add up to 5: 2 and 3.

3. 2/6 = 1/3, and 3/6 = 1/2

4. The factors are 3x+1 and 2x+1.

6x² + 5x + 1 = (3x + 1) (2x + 1)

8 0
3 years ago
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