<span>Jerry is 8 years younger than Patricia, so:
(1): Jerry = Patricia - 8
Six years ago, Patricia was 3 times as old as Jerry was then, so:
(2): (Patricia - 6) = (Jerry - 6)*3
Putting equation 1 in to equation 2
(Patricia - 6) = (Patricia - 8 - 6)*3
Patricia - 6 = 3Patricia - 42
36 = 2Patricia
Patricia = 18
And so Jerry = 10</span>
The answer for the last one is-36
Answer:
It has a period of 180 degrees.
which equals (1/2) PI
Step-by-step explanation:
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
E(29/4,3)
Step-by-step explanation:
Given that,
Segment CD has point E located on it such that CE:ED = 3:5
The coordinates of C and D are (5, -6) and (11,18) respectively.
We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :
So, the coordinates of E are (29/4,3).
