Your answer is A Since Z is width and W is height
Answer:
The area of the shaded region is 0.9082.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value, which is the area of the shaded region, is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Area of the shaded region:
pvalue of Z



has a pvalue of 0.9082
So
The area of the shaded region is 0.9082.
Answer:
\dfrac{3}{2}\pi = \green{A_s}
2
3
π=A
s
Step-by-step explanation:
Answer:
Step-by-step explanation:
6. 0 ,234,560 is divisible by 2.
7. 389,570 is divisible by 5.
8. 630,620 is divisible by 10.
9. 6+1+1+8+1=17 +(1)
611,811 is divisible by 3.
10. 5+2+5+4+3=19
multiple of 9 are 9,18,27,...
to make the sum 27 we have to add 8 to 19.
525,438 is divisible by 8.
Answer:
15 students (30% of the students in class) scores a 95 on a quiz.
Therefore the total number of students (100% of the students) in class is:
N = 15 x 100/30 = 50 (students)
(This calculation is inferred from a ratio that 15/N = 30/100).
Denote the number of students who scored a 95 on a quiz is a, the total number of students in class is b.
Then the equation that related a and b is:
b = (100/30) x a
Hope this helps!
:)