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DENIUS [597]
4 years ago
5

If BC=CD=DE, what is th area of triangle ACD.

Mathematics
1 answer:
Lena [83]4 years ago
8 0
I think 25 because 5×5 is 25
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Turkey tastes like napkins
vesna_86 [32]
So you ate napkins before? And some turkey is dry lol
4 0
4 years ago
12 points help fast I need help
dimaraw [331]

Answer:

  • False, False, True, True

Step-by-step explanation:

1

  • IQR's
  • Ride A: 30 - 20 = 10
  • Ride B: 30 - 10 = 20
  • False, as 10 < 20

2

  • Medians
  • Ride A: 25
  • Ride B: 20
  • False, as 25 > 20

3

  • Ranges
  • Ride A: 45 - 5 = 40
  • Ride B: 35 - 0 = 35
  • TRUE, as 40 > 35

4

  • Minimum
  • Ride A: 5
  • Ride B: 0
  • TRUE, as 0 < 5
4 0
3 years ago
Read 2 more answers
I'm almost positive that the answer is C; no solution. But is it possible to graph that?
andrew-mc [135]
Hi again!


Yes the correct answer is C - There are no solution.

I'm not gonna solve it since you already got the right answer.

Now how do we graph?

We cannot solve this. I used different online graphing calculator but none of them graphed it.


I hope this helps again!

7 0
3 years ago
Which is the graph of y = cos(x) + 3?<br> 1<br> N<br> 0
adoni [48]

Answer:N

Step-by-step explanation:

4 0
3 years ago
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
4 years ago
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