Hi there
I am glad to help you
6x² + 7x - 5 = 0
In this case, you need to factor the left side of the equation
(3x + 5)(2x - 1) = 0
Now set factor equal to zero (0)
3x + 5= 0 or 2x - 1 = 0
x = -5/3 or x = 1/2
I hope that's help, if you don't understand please let me know !
Answer:
I'm not sure if you mean the type of triangle or the other number but I'm pretty sure it's an equilateral triangle and the the number is 8.
Step-by-step explanation:
No, for thing 2x and 3x have different slopes. moreover they have different y and x intercepts. you can set them equal to find an intersection since they don't have the same slope but yea
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
