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jonny [76]
3 years ago
12

An apprentice productively working a 40-hour week earns more wages and is worth considerably more to the local union and the ind

ustry than one who works only 30 hours per week. Consider two apprentices, A and B, working the same job at the same scale. Apprentice A works 40 hours and is paid $160.00 from which $4.80 is paid to the local union. Apprentice B only works 30 hours. How much will the local union receive in dues for the 30 hours work?
Mathematics
1 answer:
zvonat [6]3 years ago
4 0
$3.60

You can get this by determining that the rate of which they are paid is $4 an hour (divide the total by the amount of hours). Then you can find the rate of which they collect dues by dividing the amount they paid by their total (3%). 

Using those numbers you can find the total amount the second person paid. 
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More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

7 0
2 years ago
Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively. Planes Q and R are parallel. Plane Q conta
natita [175]

Answer:

They are skew lines.

Step-by-step explanation:

Which statement is true about lines a and b?

They are parallel lines.

They are perpendicular lines.

They are skew lines.

They will intersect.

As they both are in different directions they are skew lines .

Skew lines are not parallel neither they .They are also not co planar i.e they lie in different planes.

We have two plane Q and R . We have two line a and b on the different planes Q and R. Both planes are parallel but the lines a and b are in different directions. Therefore they are skew lines . They do not intersect and are also not parallel neither co planar.

7 0
3 years ago
Kylie drew a circle with a diameter of 8 cm. Paige drew a circle with a radius of 3 cm. Approximately how much larger is the are
Lapatulllka [165]
The area for a circle with a diameter of 8 cm is 50.24 cm². The area of a circle with a radius of 3 cm is 28.26 cm². 50.24 - 28.26 =  21.98 cm. So the difference is 21.98 cm.
4 0
3 years ago
Read 2 more answers
Question 1<br><br> Which of the following is NOT linked to cardiovascular disease
Anestetic [448]
Unsaturated fat is the correct answer
4 0
2 years ago
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