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Paul [167]
4 years ago
11

What is the solution of the following equation? -6p + 7=3(2p - 3) -4 (-10 + 4p)

Mathematics
1 answer:
saul85 [17]4 years ago
5 0

Answer:

p=6

Step-by-step explanation:

- 6p + 7 = 3(2p - 3) - 4( - 10 + 4p) \\

p = 6

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This is an incomplete question, the image is shown below.

Answer : The fraction empty container is, \frac{7}{12}

Step-by-step explanation :

As we are given that:

The capacity of container = 60 mL

In the given figure, the container is filled with 25 mL.

That means,

60 - 25 = 35 mL container is empty.

Now we have to calculate the fraction of it is empty.

The fraction of it is empty = \frac{\text{Capacity of empty container}}{\text{Total capacity of container}}

The fraction of it is empty = \frac{35mL}{60mL}

The fraction of it is empty = \frac{7}{12}

Therefore, the fraction empty container is, \frac{7}{12}

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4 years ago
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

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