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3 years ago

10

Linda opened a savings account with $450. She saves $225 per month. Joe opened his savings account the same month with $750. He

saves $125 per month. How much more will Linda have in her savings account after 12 months?

1 answer:

erastova [34]3 years ago

5 0

Linda has $900 more than Joe in her bank account

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a line passes through point (-2,5) and has a slope of 2/3 points a (x,3) and b ( -2, y) lie on the line what is the value of y a

Tomtit [17]

Answer:

The value of y is 5 , and The value of x is - 5

Step-by-step explanation:

Given as :

The line passes through point ( - 2, 5)

The slope of line is m = $\frac{2}{3}$

Equation of line is written as

y - $y_1$ = m × (x - $x_1$ )

Since line passes through line ( - 2 , 5 ) and have slope $\frac{2}{3}$

So, y - 5 = $\frac{2}{3}$ × (x + 2)

Or, 3 × ( y - 5 ) = 2 × ( x + 2 )

Or, 3 y - 15 = 2 x + 4

Or, 3 y - 2 x - 19 = 0 is the equation of line

Now points ( x , 3 ) lies on the line 3 y - 2 x - 19 = 0

So, 3 × 3 - 2 x - 19 = 0

or, 9 - 2 x - 19 = 0

or, 2 x = - 10

∴ x = - $\frac{10}{2}$

I.e x = - 5

Again points ( - 2 , y ) lies on the line 3 y - 2 x - 19 = 0

So, 3 × y + 2 × 2 - 19 = 0

Or, 3 × y + 4 -19 = 0

or, 3 y = 15

∴ y = $\frac{15}{3}$

I.e y = 5

Hence The value of y is 5 , and The value of x is - 5 . Answer

8 0

3 years ago

Question 2 of 7

slamgirl [31]

2 times 8 x 12

192

2 times 5 x 8

80

2 times 12 x 5

60

192+80+60=332 ft^2

8 0

3 years ago

Read 2 more answers

A store manager did a study to determine the amount of money the first 50 customers spent in her store. The data are approximate

MatroZZZ [7]

P(x > 35) = 1 - P(x < 35) = 1 - P[z < (35 - 29.60)/10.50] = 1 - P(z < 0.5143) = 1 - 0.6965 = 0.3035

Therefore, answer is 0.30 to the hundredths place.

6 0

3 years ago

how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an

drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

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4 0

1 year ago

sam thought of a number between ten and twenty then sam gave a clue when you count by twos and when you count by threes but not

tatuchka [14]

Sorry I do not know the answer to that

8 0

3 years ago