Answer:
117
Step-by-step explanation:
x = 15 + 4y that is what I got out of it
Yes, you are correct. The answer to your problem is indeed 4.
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
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3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
