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deff fn [24]
3 years ago
12

Please help me with this! ASAP

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

The question gives you 4 different numbers that could be x, so you have to replace each x in each problem and solve. If the two answers are equivalent, that is your answer. For the first one, 6 times 2 is 12, minus 2 is 10. 5 times 2 is 10, plus 3 is 13. 10 is not equal to 13, so that is not the answer. For 5, 6 times 5 is 30, minus 2 is 28. 5 times 5 is 25, plus 3 is 28, so therefore the answer is x=5

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If triangle PQR is similar to SQT, find the value of
ankoles [38]

Answer:

x = 31.4

PQ = 58.8

Step-by-step explanation:

Set up a proportion:

SQ/QP = ST/PR

Substitute in the values they give you:

\frac{x-9}{x-9+x+5}  = \frac{8}{21}

\frac{x - 9}{2x - 4} = \frac{8}{21}

21x - 189 = 16x - 32\\5x = 157\\x = 31.4

This means that PQ = 2x - 4 = 2(31.4) - 4 = 62.8-4 = 58.8

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3 years ago
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lorasvet [3.4K]
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5 0
3 years ago
If R is the midpoint of QS, RS= 2x - 4, ST = 4x-1, and RT = 8x - 43, find QS.
Pepsi [2]

Answer: QS=68 units

Step-by-step explanation:

<em>RT=RS+ST</em>

<em>8x-43=2x-4+4x-1</em>

<em>8x-43=6x-5</em>

<em>8x-43-6x=6x-5-6x</em>

<em>2x-43=-5</em>

<em>2x-43+43=-5+43</em>

<em>2x=38</em>

<em>Divide both parts of the equation by 2:</em>

<em>x=19</em>

<em>QS=RS+RQ</em>

<em>As, RS=RQ</em>

<em>QS=2RS</em>

<em>QS=(2)((2)(19)-4))</em>

<em>QS=(2)(38-4)</em>

<em>QS=(2)(34)</em>

<em>QS=68</em>

6 0
10 months ago
The sum of three numbers is -2. The sum of three times the first number, twice the second number, and the third number is nine.
Anna35 [415]

Answer:

The numbers are 3, 5, -10.

Step-by-step explanation:

Let, the numbers are X, Y, Z.

Given, sum of the three numbers are -2.  

So, the equation is X + Y+ Z = -2 .......(i)

Again, for 2nd condition, the equation will be  

3X + 2Y + Z = 9  ....... (ii)

Again, for the third condition, the equation will be

Y - (Z/2) = 10 ......(iii)

Multiplying the equation (i) by 3 and the equation (ii) by 1, we get

                     3X + 3Y+ 3Z = -6

<u>                      3X + 2Y +  Z =  9</u>

(Deduct)                  Y + 2Z = -15 ......(iv)  

Solving equation (iii) and (iv) we get,

                         Y - (Z/2) = 10

<u>                          Y + 2Z   = -15</u>

(Deduct)        -(Z/2) - 2Z = 25

or, (-Z-4Z)/2 = 25

or, -5Z = 25*2

or, Z = 50/(-5)

Therefore, Z = -10

Putting the value of Z into equation (iv) we get,

Y + 2*(-10) = -15

or, Y - 20 = -15

or, Y = 20 - 15

Therefore, Y = 5

Putting the value of Y and Z into equation (i) we get,

X + 5 + (-10) = -2

or, X + 5 - 10 = -2

or, X - 5 = -2

or, X = 5 - 2

Therefore, X = 3

So, the numbers are, X = 3; Y = 5; and Z = -10.

8 0
3 years ago
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