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Zepler [3.9K]
3 years ago
13

Please help me and if you can, could you please explain. Thank you :D

Mathematics
2 answers:
kogti [31]3 years ago
5 0

Answer: you said help so I’m not going to give the actual answer, just how to do it.

Step-by-step explanation:

You have to find the answer first. You work out the top and then you work out the bottom. Then divide the top by the bottom. YIU will get a number woth a power. The power is x that is your answer.

Romashka [77]3 years ago
4 0

Answer:

Step-by-step explanation:

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Suppose that $3$ is a factor of $a$, $a$ is a divisor of $12$, and $a$ is positive. What is the number of possible values of $a$
antiseptic1488 [7]

If a is a divisor of 12, then

a \in \{-12, -6, -4, -3, -2, -1, 1, 2, 3, 4, 6, 12\}

If 3 is a factor (i.e. divisor) of a, then a can only be one of the elements of this set that are multiples of 3, so

a \in \{-12, -6, -3, 3, 6, 12\}

But a is positive, so there are 3 possible values a can have.

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2 years ago
What is the sum of the two vectors (-1,-4) and (3,5)
o-na [289]

Answer:

Step-by-step explanation:

a(-1, -4)\\b(3, 5)\\a + b(2, 1)

5 0
3 years ago
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Which of the following equations is nonlinear?
Mice21 [21]

Answer:

D)y=5x³ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌

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3 years ago
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Solve for x <br> help ASAP
puteri [66]

Answer: x=6 and the angle is 50

Step-by-step explanation:

1. a whole triangle = 180°

2. subtract 70 and 60 to get 50

3. subtract 2 from 50 and get 48

4. divide 48 by 8 and you get 6.

hope this helps :) everyone reading this have a great day!

7 0
3 years ago
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
4 years ago
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