Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15= 4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.
Hope I help! :D
I think the on in the top right is the answer.
Identify the length of both bases. The bases are the two parallel sides of the trapezoid. ...
Add the lengths of the bases. Add 8 cm and 13 cm. ...
Identify the height of the trapezoid. ...
Multiply the sum of the lengths of the bases by the height. ...
Divide the result by two.
<u>please mark as brainliest <3</u>
The answer is 26 because you would look at the seven to see what to round it to and since seven is greater than five, you round the number to 26.
Problem 1
<h3>Answer: B. M<3 would need to double.</h3>
Explanation: This is because angles 3 and 6 are congruent corresponding angles. Corresponding angles are congruent whenever we have parallel lines like this. If they weren't congruent, then the lines wouldn't be parallel. We would need to double angle 3 to keep up with angle 6.
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Problem 2
<h3>Answer: D. none of these sides are parallel</h3>
Explanation: We have angles A and C that are same side interior angles, but they add to A+C = 72+72 = 144, which is not 180. The same side interior angles must add to 180 degrees for parallel lines to form. This shows AB is not parallel to CD.
A similar situation happens with angles B and D, since B+D = 108+108 = 216. This also shows AB is not parallel to CD. We can rule out choices A and C.
Choice B is false because AD is a diagonal along with BC. The diagonals of any quadrilateral are never parallel as they intersect inside the quadrilateral. Parallel lines never intersect.
The only thing left is choice D. We would say that AC || BD, since A+B = 72+108 = 180 and C+D = 72+108 = 180, but this isn't listed as an answer choice.
