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Soloha48 [4]
4 years ago
12

1. One day at the farmer's market, a customer

Mathematics
1 answer:
lesya692 [45]4 years ago
8 0

Answer:

She will get back $16.49

Explanation:

3.25+0.26=$3.51

$20-$3.51=$16.49

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Tell whether –4 is a solution of the inequality.<br> —3x + 2 &lt; 15. YES OR NO?
NikAS [45]

Answer:

YES

Step-by-step explanation:

-3 times -4 = 12

12 + 2 = 14

14 < 15

7 0
3 years ago
5x-8=37 find the value of x
Andrej [43]
Because <span>−8</span><span> does not contain the </span>variable<span> to solve for move it to the other side of the </span>equation<span> by adding </span>8<span> to both sides.
</span><span>5x=8+37

</span>Add 8<span> and </span>37<span> to get </span><span>45.
</span><span>5x=45

</span>Divide<span> each </span>term<span> by 5.
</span>x=<span>9
</span>

x is equal to 9
3 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)<br> thanks!
fredd [130]

Answer:

A is correct, x=7, AB=20

Step-by-step explanation:

All of the options say x=7 so you can just input 7 into 4x-8 to find AB

4(7)-8=AB

28-8=AB

20=AB

Hope this helps, please mark brainliest :)

3 0
3 years ago
How many x-intercepts does the graph of y=2x^2-4x+2 have?<br> A.) 2<br> B.)1<br> c.)0
ASHA 777 [7]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
The following data set represents the age of
Julli [10]

\huge\text{Hey there!}


\huge\textsf{Breaking the meaning down in simpler terms}
\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}


\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}

\huge\textsf{Formulas for each term}

\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }


\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}


\huge\textbf{SOLVING FOR THE QUESTION}

\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of  \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}

\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}

\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}


\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
~\frak{Amphitrite1040:)}</h3>
8 0
3 years ago
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