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Softa [21]
4 years ago
14

In the diagram, ABC=ECD. Which statement is true?

Mathematics
1 answer:
Ne4ueva [31]4 years ago
4 0
If you showed me the diagram I could give you an answer.
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Can someone help me please!
Hatshy [7]
So we’re looking how many combinations we can make by selecting 5 items in a group of 17.

So we use n C r.

Where I the number of combinations of n objects taken r at a time.

So, 17 C 5

17! / (17-5)! 5! = 6188

(I hope this is correct)
3 0
3 years ago
Sara and her friends are enjoying a bag of candy-coated chocolates. Just for fun, they remove 80 pieces of candy from the bag to
Zepler [3.9K]
The answer to your question is C
5 0
4 years ago
Read 2 more answers
What is the value of the product (3-2)(3+21)?<br> 5<br> 9 +41<br> 9-41<br> 13
liraira [26]
(3 - 2)(3 + 21) = 9 + 63 - 6 - 42 = 72 - 6 - 42 = 66 - 42 = 24 (I got 24 as my final answer)
8 0
4 years ago
Read 2 more answers
What is the answer to this problem Using the scale 1 in. : 4 m, Mika calculated the length, or the longer side of the ballroom,
madreJ [45]
We know that
with
scale factor 1=1 in/4 m
<span>the longer side of the ballroom------->  44 m
scale factor= measure model/measure actual
measure model=scale factor*measure actual
</span>measure model=(1/4)*44------> 11 in

with
 scale factor 2=1 in/7 m
measure actual=measure model/scale factor
measure actual=11/(1/7)-----> 77 m

the answer is 
77 m

4 0
3 years ago
Read 2 more answers
For what values of h are the vectors [Start 3 By 1 Matrix 1st Row 1st Column negative 1 2nd Row 1st Column 4 3rd Row 1st Column
Bogdan [553]

Answer:

The set is linearly dependent for every value of h.

Step-by-step explanation:

Recall that a set of vector {a,b,c,d} is a linearly dependent set of vectors if any of the vectors can be written as a linear combination of the other ones.

We are given the following vectors.a=(-1,4,6), b=(5,2,-3), c=(3,-5,-4), d=(12,-20, h). At first, we will check if a,b,c are linearly independent. To do so, we will calculate the following determinant (the procedure of the calculation is omitted).

\left|\begin{matrix}-1 & 5 & 3 \\ 4 & 2 & -5 & \\ 6 & -3 & -4\end{matrix}\right| = -119\neq 0

Since the determinant is not zero, this implies that the vectors a,b,c are all linearly independent. Since a,b,c are all vectors in \mathbb{R}^3 which is a 3-dimensional space, and they are 3 linear independent vectors, then they are automatically a base of this space. Consider now the vector d. Since {a,b,c} is a base of \mathbb{R}^3, then it generates any vector of this space(i.e any other vector of the space is a linear combination of {a,b,c}). In particular, d. So the set {a,b,c,d} is linearly independent for any value of h

3 0
3 years ago
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