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kolbaska11 [484]
4 years ago
14

The perimeter of a rectangle can be found using the expression 2/ +2w where I represents length and e represents width. Find the

perimeter of the front of a new building whose length is 120 ft and width is 90 ft
Mathematics
1 answer:
Snezhnost [94]4 years ago
5 0

Answer:

420

Step-by-step explanation:

You might be interested in
WILL GIVE BRAINLIEST!!! Show your work please!!
Setler79 [48]

Solution:     =====>       -7 + {12 - 3[50 - 4(2 + 3) ] }   ======>     -85



Simplify :

−7     +    12      −     3(50    -       4(2      +      3))

=         5     −   3(50   −    4(2      +      3))

=         5     −     3(50     −        (4)(5))

=        5     −     3(50   −    20)

=        5    −     (3)(30)

=         5     −     90

=      − 85

Answer   ========>        -85





Hope that helps!!!!                                                     : )

8 0
3 years ago
I need help I dont understand
svp [43]

Answer:

X=5

mde=e

mef=5

mdfg=77

Step-by-step explanation:

6 0
3 years ago
Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:
Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

3 0
4 years ago
A right rectangular prism with square bases has a height of 20 centimeters and a volume of 800 cubic centimeters.
nignag [31]

Answer:

The length of a side of the base is 20 centimeters.

The area of a lateral side between the bases is about 126.5 square centimeters.

Step-by-step explanation:

It's a rectangular prism with a total volume of 800 cu cm, and a height of 20 cm.

So, the base has an area of...  800/20 = 40 sq cm.

The prism is a cube.   NO.  If it was a cube, the base would be 400 sq cm (20x20), since the height is 20.

The diagonal of the base is 4 centimeters. NO. with a base of 40 sq cm, it's impossible to have a diagonal of 4 cm.  A diagonal would form a hypotenuse... and an hypotenuse is longer than the two other sides... an hypotenuse of 4 would mean for example sides of about 2 and 3...  which gives 6 sq cm for the base, not 40.

The length of a side of the base is 20 centimeters.  COULD BE. The base is 40 sq cm, it could have a side of 20 and the other of 2.  Without knowing more about the prism than what's included in the question, we can't say YES and we can't say NO.

The area of a base is 40 square centimeters.  Yes

The area of a lateral side between the bases is about 126.5 square centimeters. YES, since the height is 20, that would mean one side of the base would be roughly 6.325 cm... for a base area of 6.325 x 6.325 = 40 sq cm.

7 0
3 years ago
Read 2 more answers
Use substitution to determine which of the following points is a solution to the standard form equation below. 2y = 5
sashaice [31]
The question is incomplete.

This is the complete question as I found in internet:

<span>Use substitution to determine which of the following points is a solution to the standard form equation below 5x-2y = 10

these are the points:
</span>
-1,5

1,5

0,-5

0,5

Answer: (0, -5)

Explanation:


point          x           y        5x - 2y = 10 ?


-1,5         -1           5         5(-1) - 2(5) = - 5 - 10 = - 15 ≠ 10 ⇒ not a solution

1,5            1          5         5(1) - 2(5) = 5 - 10 = 5 ≠ 10 ⇒ not a solution
 
0,-5           0        -5           0 -2(-5) = 10 ⇒ a solution

0,5             0         5          0 - 2(5) = - 10 ≠ 10 ⇒ not a solution

7 0
4 years ago
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