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kolbaska11 [484]
4 years ago
14

The perimeter of a rectangle can be found using the expression 2/ +2w where I represents length and e represents width. Find the

perimeter of the front of a new building whose length is 120 ft and width is 90 ft
Mathematics
1 answer:
Snezhnost [94]4 years ago
5 0

Answer:

420

Step-by-step explanation:

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Can anyone solve for x? ​
seraphim [82]

Answer:

if all the corners are 90 degree angles:

x = -12

Step-by-step explanation:

2x+3 = x-9

x = -12

6 0
3 years ago
Read 2 more answers
Number 16. Find the measure of angle J. Correct answer will get brainliest.
adoni [48]
Download "Photomath" very helpful app. (Gives Answers with a picture of the problem)
3 0
3 years ago
Solve using substituion -5x + y = -2 -3x + 6y = -12
sergiy2304 [10]

Answer:

<h2>x = 0</h2><h2>y = - 2</h2>

Step-by-step explanation:

-5x + y = -2………… Equation 1

-3x + 6y = -12 ………… Equation 2

Using substitution

Make y the subject in equation 1 and substitute it into equation 2 and solve for x

That's

y = 5x - 2

We have

- 3x + 6( 5x - 2) = - 12

- 3x + 30x - 12 = - 12

27x = - 12 + 12

27x = 0

Divide both sides by 27

x = 0

Substitute x = 0 into y = 5x - 2

We have

y = 5(0) - 2

y = - 2

So the solutions are

<h3>x = 0 </h3><h3>y = - 2</h3>

Hope this helps you

4 0
3 years ago
If the circumference of the circle is 72 what is the minor arc of a 60 degree angle
telo118 [61]
The circumference involves 360 degrees.
60 degrees is one sixth of the circle (60/360)
So, one sixth of 72 is 12.


6 0
4 years ago
Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
4 years ago
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