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liraira [26]
3 years ago
9

6x-5 = -6(x+2) I keep getting an incorrect fraction answer please help

Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

x = -7/12 or -0.583.. repeating.

Step-by-step explanation:

6x-5= -6(x+2)

___________ (distributive property)

(to group like terms)

6x-5 = -6x-12

___________ (addition poe) (add 6x on both sides to cancel -6 out)

+6x +6x

___________

12x-5 = -12

__________

+5 +5 (addition poe) (add 5 to both sides to cancel -5 out)

__________

12x = -7

__________

÷12 ÷12 (division poe) (divide both sides by 12 to get x)

x = -7/12

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What is the range for the graph shown?
Andrej [43]

Answer:

D. -2 ≤ y ≤ 3

Step-by-step explanation:

This is because range is based on y-values and so the lowest y-value here is -2 and the greatest one is 3, inclusive.

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Is -8-2(3+2n) +7 equivalent to -30-13n
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NO

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Jamie is hiking up a small mountain. He climbs up at a constant rate of 300 feet/hour until he reaches the peak at 1,500 feet. A
aleksandr82 [10.1K]

Answer:

a. d = 1500 - 300t. b. after 2 hours and after 4 hours

Step-by-step explanation:

a. Since Jamie hikes up the mountain at a rate of 300 ft/hr, and the mountain is 1500 ft high, his distance, d from the peak of the mountain at any given time,t  is given by

d = 1500 - 300t.

b.If Jamie distance d = 900 ft, then the equation becomes,

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

The equation d = 1500 - 300t. also models his distance from the peak of the  mountain if he hikes down at a constant rate of 300 ft/hr

At d = 900 ft, the equation becomes

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

So, on his hike down the mountain, it takes him another 2 hours to be 900 ft from the peak of the mountain.

So, he is at 900 ft on his hike down after his start of hiking up the mountain at time t = (2 + 2) hours = 4 hours. Since it takes 2 hours to climb to the peak of he mountain and another 2 hours to climb down 900 ft from the peak of the mountain.

4 0
3 years ago
The researchers are concerned that the dollars spent per shopper examined in the study is too different from what has been found
Katarina [22]

Answer:

Step-by-step explanation:

Hello!

To study if the average dollars spend per shopper is different than the expected population average of $84.5 there was a sample of 120 shoppers taken and their spending habit registered.

Then the study variable is:

X: Amount of money spent by a shopper ($)

This population standard deviation is σ= $16

Using the data information I've run a normality test, with p-value: 0.3056 against the test significance level α: 0.05, the decision is to not reject the null hypothesis so there is enough statistical evidence to conclude that the study variable has a normal distribution.

X~N(μ;σ²)

I've also calculated the sample mean and standard deviation:

X[bar]= $81.01

S= $19.62

a.

If the objective is to test that the true mean spending for the population is significantly different than the expected average of 84.5, the parameter of interest is the population mean μ and the hypothesis test will be two-tailed.

H₀: μ = 84.5

H₁: μ ≠ 84.5

α:0.05

The statistic is a standard normal for one sample:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

Z_{H_0}= \frac{81.01-84.5}{\frac{16}{\sqrt{120} } } = -2.389

p-value two tailed  0.016894

b.

The decision rule using the p-value method is:

If p-value ≤ α ⇒ Reject the null hypothesis.

If p-value > α ⇒ Do not reject the null hypothesis.

Since the p-value is less than the significance level, the decision is to reject the null hypothesis.

c.

Using a level of significance of 5% the null hypothesis was rejected. So there is enough statistical evidence to support the researcher's claim that the true mean spending for the population is significantly different than the expected average of $84.5.

I hope it helps!

3 0
3 years ago
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