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OleMash [197]
3 years ago
5

Help me! I need the surface area and volume please explain how you got that answer!

Mathematics
1 answer:
solong [7]3 years ago
5 0

dhdhdjdbdmdhbsdkdbfb

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Anyone knows #3 and 4 answers ?
UNO [17]
3.saven. 4.2and5 Third
4 0
3 years ago
51. (08.02 MC) Box A has a volume of 48 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were double
Vanyuwa [196]

Answer:

384 m³

Step-by-step explanation:

Let the dimension of box a be l,b, and h.

ATQ,

lbh = 48 .....(1)

If we double the dimension of box A, we get box B whose new dimensions will be 2l,2b and 2h.

Let V be the volume of box B.

V = (2l)(2b)(2h)

V = 8(lbh)

= 8(48) [from equation (1)]

= 384 m³

Hence, the volume of the box B is 384 m³.

7 0
3 years ago
Consider a circle that has a circumference of 28/3.14 centimeters. What is the area of this circle? Answer fast plz also can you
bija089 [108]

Answer:

A=6.33\ cm^2

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=\frac{28}{3.14}\ cm

\pi=3.14

substitute the values

\frac{28}{3.14}=2(3.14)r

r=\frac{28}{19.7192}\ cm

r=1.42\ cm

step 2

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

substitute the values

A=(3.14)(1.42)^{2}

A=6.33\ cm^2

7 0
4 years ago
Divide. 15÷−5 Drag and drop the correct number into the box to complete the sentence. The quotient is Response area.
german

Answer:

15÷-5=-3

Step-by-step explanation:

8 0
3 years ago
Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
4 years ago
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