2y to the second power= 4y
-6y to the second power= -36y
Transformations
(x-3)...: That means the graph shifted 3 units right.
...-1: that means the graph shifted 1 unit down.
answer: 3 units right, and 1 down
Answer:
1) x = 8
2) ∠RPS = 36°
Step-by-step explanation:
<u>GIVEN :-</u>
- ∠QPS = 180°
- ∠QPR = 7x + 88
- ∠RPS = 3x + 12
<u>TO FIND :-</u>
- Value of x
- Measure of ∠RPS
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
In a straight line , if there are two angles such that their sum is equal to straight angle (or 180° in other words) , then those angles are known as linear pair.
<u>PROCEDURE :-</u>
1)
Measure of ∠QPS = 180° and it comprises of ∠QPR & ∠RPS.
⇒ ∠QPR & ∠RPS are linear pair.
⇒ ∠QPR + ∠RPS = 180°
⇒ 7x + 88 + 3x + 12 = 180°
⇒ 10x + 100 = 180
⇒ 10x = 180 - 100 = 80
⇒ x = 80/10 = 8
2)
x = 8. So,
∠RPS = 3×8 + 12 = 24 + 12 = 36°
Answer: C. Definition of an Altitude
Step-by-step explanation:
Given: In triangle MNO shown below, segment NP is an altitude from the right angle.
Let ∠MNP=x
Then ∠PNO=90°-x
Therefore in triangle MNO,
∠MPN=∠NPO =90° [by definition of Altitude]
[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]
Now using angle sum property in ΔMNP
∠MNP+∠MPN+∠PMN=180°
⇒x+90°+∠PMN=180°
⇒∠PMN=180°-90°-x
⇒∠PMN=90°-x
Now, in ΔMNO and ΔPNO
∠PMN=∠PNO=90°-x
and ∠MPN=∠NPO =90° [by definition of altitude]
Therefore by AA similarity postulate, we have
ΔMNO ≈ ΔPNO
Answer:
2.7 lb
Step-by-step explanation:
2x1.08=2.16
1/2x1.08=0.54
2.16
+ <u>0.54</u>
2.70
2.70 = 2.7
