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tino4ka555 [31]
3 years ago
10

Find the value of x in the parallelism. Please respond ASAP

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

60=x+23(opposite angle of parallelogram are equal)

60-23=x

x=37 is answer.

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A puppy’s circular water bowl has a radius of 14 cm. Identify the two true statements.
avanturin [10]

Answer:

the diameter is 28 centimeters and the area is 97.4 centimeters

Step-by-step explanation:

the diameter is just the radius plus the radius so its 28

and i just solved for the area and got 97.4

6 0
3 years ago
lauren is saving for gymnastics camp camp cost 225 attend she got 40 percent of the money saved how much money has she saved
Mila [183]

She has saved 90 dollars

5 0
3 years ago
The sum of 10 times a number and fifteen is added to 11 times the same number. (how do i make this into a algebraic expression?)
Ne4ueva [31]
10a times (15+11) or 10a times 26
6 0
3 years ago
An employment agency specializing in temporary construction help pays heavy equipment operation $138 per day and general laborer
ki77a [65]
<h3>17 heavy equipment operators and 14 general labourers were employed</h3>

<em><u>Solution:</u></em>

Let x = number of heavy equipment operators employed

Then,

31 - x = number of laborers employed

From given,

Pay of heavy equipment operators = $ 138 per day

Pay of general labours = $ 93 per day

Payroll was $3648

Therefore,

number of heavy equipment operators x Pay of heavy equipment operators + number of laborers employed x Pay of general labours = 3648

138x + 93(31 - x) = 3648

138x + 2883 - 93x = 3648

45x = 3648 - 2883

45x = 765

x = 17

Thus,

31 - x = 31 - 17 = 14

Therefore, 17 heavy equipment operators and 14 general labourers were employed

6 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
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