Can someone help me, im really stuck.

Mathematics

2 answers:

tresset_1 [31]2 years ago

5 0

Answer:

(x/4) +1 OR (4/x)+1

Step-by-step explanation:

Vaselesa [24]2 years ago

4 0

Answer:

1/4x+1

Step-by-step explanation:

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Use the grouping method to factor this polynomial. x^3+2x^2+7x+14

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x3+2x2-7x-14

Factor out the greatest common factor from each group.

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x2(x+2)-7(x+2)

Factor the polynomial by factoring out the greatest common factor,

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2 years ago

Solve for x ln 5 + ln x + 3

olchik [2.2K]

4 is the correct answer i believe! :) sorry if wrong.
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2 years ago

Read 2 more answers

Really need help guys! Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$