All categories

3 years ago

The clear formatting button can be found in the group on the tab.

1 answer:

8 0

The answer would be font group; home. We use the clear formatting button if you want to delete the style, effects of the text and the font formatting in the document. So to do this, select the text you want to clear the formatting then go to the home tab, in the font group, look for the clear formatting.

You might be interested in

When two sticks are laid end-to-end they cover a length of 8.32 feet. One stick is 2.93 ft longer than the other. What is the le

77julia77 [94]

To solve this problem we will start by defining the length of the shortest stick as 'x'. And the magnitude of the longest stick, according to the statement as

$x+2.93$

Both cover a magnitude of 8.32 ft, therefore

$x +(x+2.97) = 8.32$

Now solving for x we have,

$x + (x + 2.93) = 8.32$

$2x + 2.93 = 8.32$

$2x = 8.32 - 2.93$

$x = \frac{ 8.32 - 2.93}{2}$

$x = 2.695 ft$

Therefore the shorter stick is 2.695ft long.

7 0

4 years ago

An object with a mass of 0.5 kilometre start from rest and achieves a maximum speed of 20 metre per second in 0.01 second, what

Katarina [22]

Answer:

Hiii how are you doing??I don't understand that

3 0

3 years ago

Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge b

Elena L [17]

Answer:

a) 0.167 μC/m^2

b) 1.887 * 10^4 V/m

Explanation:

Hello!

First let's find the surface charge density:

Since thesatellite is metallic, the accumalted charge will be uniformly distribuited on its surface. Therefore the charge density σ will be:

σ = Q/A

Where A is the area of the satellite, which is:

A=4πr^2 = πd^2 = π(1.9m)^2

Therefore:

σ = (1.9)/(π (1.9)^2) μC/m^2 = 0.167 μC/m^2

Now let's calculate the electric field

Just outside the surface of the satellite the elctric field will be:

E = σ/ε0

Where ε0=8.85×10^−12 C/Vm

Therefore:

E = (0.167*10^-6 C/m^2) / (8.85*10^-12 C/Vm) = 0.01887 *10^6 V/m

E = 1.887 * 10^4 V/m

5 0

3 years ago

What happens to the wavelength of a wave if you increase the frequency?

dezoksy [38]

The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave in whatever material it's traveling through. So if the
frequency is increased, then the wavelength must decrease by the same
factor, in order to keep the product the same.

4 0

3 years ago

Could anyone help me for this question please!! Really emergency!!!

kodGreya [7K]

16/9 m/s^2
negative 4/3 m/s^2
14 m/s
the last one is too detailed to do in my head while on the bus; sorry

5 0

3 years ago

The clear formatting button can be found in the ____ group on the ____ tab.

The clear formatting button can be found in the group on the tab.