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3 years ago

The clear formatting button can be found in the group on the tab.

1 answer:

8 0

The answer would be font group; home. We use the clear formatting button if you want to delete the style, effects of the text and the font formatting in the document. So to do this, select the text you want to clear the formatting then go to the home tab, in the font group, look for the clear formatting.

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A block of mass 0.404 0.404 kg is hung from a vertical spring and allowed to reach equilibrium at rest. As a result, the spring

VARVARA [1.3K]

To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.

We know that the Force can be defined as

$F = xk \rightarrow mg = kx \Rightarrow k = \frac{mg}{x}$

Where

k = Spring constant

x = Displacement

g = Gravity

m = mass

At the same time the period of a spring mass system is defined as

$T = 2\pi \sqrt{\frac{m}{k}}$

Where

m = Mass

k = Spring constant

Our values are given as,

m = 0.404kg

x = 0.666m

Replacing to find the value of the Spring constant we have that

$k = \frac{mg}{x}$

$k = \frac{(0.404)(9.8)}{0.666}$

$k = 5.944N/m$

Now using the formula of the period we know that

$T = 2\pi \sqrt{\frac{m}{k}}$

$T = 2\pi \sqrt{\frac{0.404}{5.944}}$

$T = 1.638s$

Finally, if the oscillation was 0.359m

The maximum height will be determined by the total length of that oscillation being equivalent to

$h=2a$

$h = 2*0.359$

$h = 0.718m$

4 0

3 years ago

A car traveling at a constant speed travels 175 miles in 4 hours. How many feet will the car travel in 10 minutes?

8_murik_8 [283]

The answer would be 70. I got my answer from www.iun.edu

8 0

3 years ago

A cube, whose edges are aligned with the , and axes, has a side length . The field is immersed in an electric field aligned with

Ivenika [448]

Complete Question

Complete Question is attached below

Answer:

$q=1.558*10^{-9}c$

Explanation:

From the question we are told that:

Side length s=1.13m

Left field strength $E_l=784.75N/m$

Right field strength $E_r=776.38 N/m$

Front field strength $E_f=725.5 N/m$

Back field strength $E_b=749.54 N/m$

Top field strength $E_t=944.95 N/m$

Bottom field strength $E_{bo}=1082.58 N/m$

Generally, the equation for Charge flux is mathematically given by

$\phi=EAcos\theta$

Where

Theta for Right,Left,Front and Back are at an angle 90

$cos 90=0$

Therefore

$\phi =0$ with respect to Right,Left,Front and Back

Generally, the equation for Charge Flux is mathematically also given by

$\phi=\frac{q}{e_o}$

Where

$Area =L*B\\\\A=1.13*1.13\\\\A=1.2769m^2$

Therefore

$Q_{net}=E_{bo}Acos\theta_{bo} +E_tAcos\theta_t$

$Q_{net}=1082.85*1.2769*cos0=944.95*1.2769cos (180)$

$Q_{net}=176N/C m^2$

Giving

$q=\phi*e_0$

$q=176N/C m^2*1.558*10^{-12}c$

$q=1.558*10^{-9}c$

4 0

3 years ago

The hindenburg zeppelin contained 200,000 m^3 of hydrogen, with a density of 0.0899 kg/m^3. What is the mass of the hydrogen?

oksian1 [2.3K]

d=m/v

0.0899=m/200000

or,0.0899*200000=m

m=17980

6 0

3 years ago

Read 2 more answers

The first astronomer to show that spiral nebulae (today called spiral galaxies) have large Doppler shifts was

solong [7]

William Parsons was the first astronomer to show that spiral nebulae have large Doppler shifts.

<h3>What are Spiral nebulae?</h3>

In space, a nebula is a huge cloud of gas and dust. Some nebulae, including multiple nebulae, are made of gas and dust that have been released from the explosion of a dead star called a supernova. There are other nebulae that are star-forming regions.
Edwin Hubble began observing Cepheid variables in many spiral nebulae, including the alleged Andromeda Nebula, in 1923, demonstrating that they are, in fact, full-fledged galaxies outside our own. Since then, the phrase spiral nebula has lost favor.
One group of astronomers believed that spiral nebulae were parts of our Milky Way galaxy, whereas the other group believed that these objects were actual galaxies that were outside of the Milky Way galaxy.

To learn more about Nebulae visit:

brainly.com/question/6452529

#SPJ4

8 0

2 years ago

The clear formatting button can be found in the ____ group on the ____ tab.

The clear formatting button can be found in the group on the tab.