Answer:
Frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)
Explanation:
We have given wavelength of the light ![\lambda =430nm=430\times 10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D430nm%3D430%5Ctimes%2010%5E%7B-9%7Dm)
Velocity of light is equal to ![v=3\times 10^8m/sec](https://tex.z-dn.net/?f=v%3D3%5Ctimes%2010%5E8m%2Fsec)
We have to find the frequency of light
We know that velocity is equal to
, here
is wavelength and f is frequency of light
So frequency of light will be equal to ![f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%20%7D%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B430%5Ctimes%2010%5E%7B-9%7D%7D%3D6.97%5Ctimes%2010%5E%7B1%7DHz)
So frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)
<span>haha I used to think biology was so hard, i find it quite easy now.
Okay, so basically Osmosis is the movement of water molecules from a higher concentration to a lower concentration. Diffusion is generally the movement of a gradient from higher concentration to an area of lower concentration. Osmosis applies to water only, whereas diffusion, you have many types such as Passive transport [ movement of molecules from high- low, NO CELLULAR ENERGY needed! ] then you have faciliated diffusion ( basically uses a channel protein to allow big substances to go through the membrane : NO ENERGY needed]
OSMOSIS, the important thing to remember is that water ALWAYS flow towards the region with the higher concentration of the solute (ex: Salt is solute, water is solvent) solute is the thing that is being dissolved. Solvent is the one doing the dissolving. Hope this helped!</span>
Answer:
The appropriate solution is "61.37 s".
Explanation:
The given values are:
Boat moves,
= 10 m/s
Water flowing,
= 1.50 m/s
Displacement,
d = 300 m
Now,
The boat is travelling,
= ![10+1.50](https://tex.z-dn.net/?f=10%2B1.50)
= ![11.5 \ m/s](https://tex.z-dn.net/?f=11.5%20%5C%20m%2Fs)
Travelling such distance for 300 m will be:
⇒ ![v = \frac{d}{t} \ sot \ t](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20%5C%20sot%20%5C%20t)
![=\frac{d}{v}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bd%7D%7Bv%7D)
On putting the values, we get
![=\frac{300}{11.5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B300%7D%7B11.5%7D)
![=26.08 \ s](https://tex.z-dn.net/?f=%3D26.08%20%5C%20s)
Throughout the opposite direction, when the boat seems to be travelling then,
= ![10-1.50](https://tex.z-dn.net/?f=10-1.50)
= ![8.5 \ m/s](https://tex.z-dn.net/?f=8.5%20%5C%20m%2Fs)
Travelling such distance for 300 m will be:
⇒ ![v=\frac{v}{t} \ sot \ t](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bv%7D%7Bt%7D%20%5C%20sot%20%5C%20t)
![=\frac{d}{v}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bd%7D%7Bv%7D)
On putting the values, we get
![=\frac{300}{8.5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B300%7D%7B8.5%7D)
![=35.29 \ s](https://tex.z-dn.net/?f=%3D35.29%20%5C%20s)
hence,
The time taken by the boat will be:
= ![26.08+35.29](https://tex.z-dn.net/?f=26.08%2B35.29)
= ![61.37 \ s](https://tex.z-dn.net/?f=61.37%20%5C%20s)
4. Grass - Caterpillar - Hedgehog - Fox
5. Caterpillar, Rabbit, Mouse.
6. Cougar and Fox.
7. Bacteria
8. The bird, hedgehog, Fox and cougar would be effected since the Hedgehogs and birds would soon die out due to the loss of their food. Once they die out, the cougar and Fox would have no predators left to eat.
Answer:
90 hp
Explanation:
Power = work / time
P = ½ (1500 kg) (25 m/s)² / 7.0 s
P = 67,000 W
P = 90 hp