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kondor19780726 [428]
3 years ago
13

What is a analogy for transition metals

Physics
1 answer:
Ganezh [65]3 years ago
6 0

<em>A simple metallic band model is proposed for the transition metal mono antimonides, by analogy to the transition metals.</em>

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The first law of thermodynamics states that . Is this also a statement of the principle of conservation of energy?
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B. Should be your answer.
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Calculate the total distance traveled (in m)
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Distance is 13m and Displacement is 9m

Explanation:

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The diagram below shows a circuit with a battery that provides an unknown potential difference. Work out the potential differenc
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I will be so thankful if u answer correctly!!​
polet [3.4K]

(C) 200 N

Explanation:

The acceleration due to gravity on earth g_{E} is given by

g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}

where G = universal gravitational constant

\:\:\:\:\:\:\:\:\:\:\:\:M_{R} = mass of the earth

\:\:\:\:\:\:\:\:\:\:\:\:R_{E} = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity g_{K} is

g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}

\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}

\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}

or

g_{K} = (\dfrac{2}{9})\:g_{E}

If we multiply both sides by Superman's mass, we get his weights on both planets:

mg_{K} = (\dfrac{2}{9})\:(mg_{E})

W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N

3 0
3 years ago
Find the acute angles between the curves at their points of intersection. (The angle between two curves is the angle between the
ladessa [460]

Answer:

1.190390345 degrees.

Explanation:

As stated in the problem that the angle between the two curves is also the angle between slopes of the two cures at the point of intersection, which is 1 (when we set two equation equal and solve for x).

We know, if you don't  you could verify it for yourself and it will be a nice mathematical exercise for you, that when there are two lines with slopes m_1 and m_2 then the angle between them and their two slopes has following relationship.

tan(\alpha ) = |\frac{m_2-m_1}{1+m_1m_2}|   where \alpha is angle between the two lines.

As it is clear that we can easily get the angle between the two curves if we know slopes at that point, which you will see in second is very straight forward to calculate.

Slopes are simply derivatives evaluated at the point of intersection and the two derivatives are D_1 16x and D_2 =24x^2, substituting x =1 we get, m_1 = 16 and m_2 = 24.

Now put m_1 and m_2 in this relationship, rearrange and solve for angle, it will come out to be

\alpha = 1.190390345 degrees.

that is our angle that we want to know between the two cures at the point of their intersection.

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3 years ago
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