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kondor19780726 [428]
3 years ago
13

What is a analogy for transition metals

Physics
1 answer:
Ganezh [65]3 years ago
6 0

<em>A simple metallic band model is proposed for the transition metal mono antimonides, by analogy to the transition metals.</em>

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Is there any way u can help me
dedylja [7]

Answer:

get help with your work

try understand your work

ask your teacher for assistance or class

or maybe cheat but understand the work first if you wanna

8 0
3 years ago
Calculate the temperature increase in a 1.00-kg sample of water that results from the conversion of gravitational potential ener
Llana [10]

To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as

PE = mgh

Where,

m= mass

g = Gravitational acceleration

h = Height

And thermal energy is obtained as

Q = mC_p\Delta T

Where,

\Delta T = Change in Temperature

C_p = Specific Heat

m = Mass

We can equate this equation and rearrange to find the change at the Temperature, then

mgh = mC_p\Delta T

\Delta T = \frac{gh}{C_p}

Our values are given as,

C_p = 4186J/Kg\cdot K \rightarrow Specific Heat Water

Using energy conservation

g = 9.8m/s^2

h = 807m

Replacing,

\Delta T = \frac{(9.8)(807)}{4186}

\Delta T = 1.89K

Therefore the temperature increase in a 1kg sample of water is 1.89K

8 0
3 years ago
What is the force acting on a 10kg object that accelerates from 5 m/s to 20 m/s in 5s?
vitfil [10]

Answer:

Option C

Explanation:

v= u + at

20 = 5 + a(5)

15= a(5)

a= 3 m/s²

Force = mass × acceleration

= 10 × 3

= 30 N

3 0
3 years ago
A girl pulls her younger brother on a sled along a flat sidewalk (the total mass of the sled is 30kg). A frictional force of 50N
harkovskaia [24]

Answer:

6.13 s

219 N

Explanation:

Newton's law in the x direction:

∑F = ma

150 cos 30° N − 50 N = (30 kg) a

a = 2.66 m/s²

Δx = v₀ t + ½ at²

(50 m) = (0 m/s) t + ½ (2.66 m/s²) t²

t = 6.13 s

Newton's law in the y direction:

∑F = ma

Fn + 150 sin 30° N − (30 kg) (9.8 m/s²) = 0

Fn = 219 N

4 0
3 years ago
Acceleration due to gravity on earth is:
Olenka [21]
C because gravity is holding everything down
5 0
3 years ago
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