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ExtremeBDS [4]
4 years ago
14

Pppppplllllleeeaaaassssseeee helllllllllpppppp mmmmmmmeeeee

Mathematics
1 answer:
Paul [167]4 years ago
8 0
You didn't show all answer choices unfortunately, but basically during neap tide, the moon is either above or below the earth, in pictures (vertical). And the right half will always be in shadow.
~Hope this helps
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Help me plz now plz help me asap​
loris [4]

\\ \sf\longmapsto 0.49=\dfrac{49}{100}

\\ \sf\longmapsto 0.093=\dfrac{93}{1000}

\\ \sf\longmapsto 0.021=\dfrac{21}{1000}

\\ \sf\longmapsto 0.103=\dfrac{103}{1000}

6 0
3 years ago
Someone give me the answers to this
strojnjashka [21]
Range: the set of all y-values of a graph or equation.

Y-intercept: the y-value where the graph intersects the y-axis.

Domain: the set of all x-values of a graph or equation.

X-intercept: the x-values where the graph intersects the x-axis.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
Find the surface area of the composite solid and round to the nearest tenth. Explain your answer.
Orlov [11]
Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.

so, for the rectangle's sides,

front and back are two 6x3 rectangles

left and right are two 6x3 rectangles

the bottom part is a 6x6 rectangle

now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.

now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.

so, just get the area of all those rectangles and the triangles, sum them up and that's the surface area of the composite,

\bf \stackrel{lateral~rectangles}{4(6\cdot 3)}~~+~~\stackrel{bottom~rectangle}{(6\cdot 6)}~~+~~\stackrel{triangles}{4\left( \cfrac{1}{2}(6)(4) \right)}
7 0
3 years ago
a right triangle has a 30 degree angle. the leg adjacent to the 30 degree angle measures 25 inches. what is the length of the ot
crimeas [40]
The length of the other leg is 14.4
8 0
4 years ago
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