Match the solid figure to the appropriate formula.

1 answer:

4 0

1. A = 1/4s squared, square root of 3 equilateral triangle
2. A = bh rectangle
3. A = pi(r) squared circle area
4. A = 1/2 h (b1+ b2) trapezoid
5. C = pi(d) circle circumference
6. A = base x altitude parallelogram
7. A = 1/2(ap) regular polygon
8. A = 1/2(bh) triangle

- regular polygon
- trapezoid
- parallelogram
- circle circumference
- equilateral triangle
- circle area

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Please help and solve for x! (: thank you in advance.

Vera_Pavlovna [14]

First look at the given numbers, especially 123 degrees which if you add up the other side it equals 180 degrees so:
180-123= 57
Ok now you know two sides of the triangle and you know that all the 3 sides add up to 360 degrees so:
57+75= 132
180-132= 48

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Given the parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π. convert to a rectangular equation and sketch the curve

Temka [501]

The rectangular equation for given parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π is $\frac{x^{2} }{4} +\frac{y^2}{9} =1$ which is an ellipse.

For given question,

We have been given a pair of parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π.

We need to convert given parametric equations to a rectangular equation and sketch the curve.

Given parametric equations can be written as,

x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.

We know that the trigonometric identity,

sin²t + cos²t = 1

⇒ (x/2)² + (- y/3)² = 1

⇒ $\frac{x^{2} }{4} +\frac{y^2}{9} =1$

This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.

The rectangular equation is $\frac{x^{2} }{4} +\frac{y^2}{9} =1$

The graph of the rectangular equation $\frac{x^{2} }{4} +\frac{y^2}{9} =1$ is as shown below.

Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is $\frac{x^{2} }{4} +\frac{y^2}{9} =1$ which is an ellipse.

Learn more about the parametric equations here:

brainly.com/question/14289251

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