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djverab [1.8K]
3 years ago
12

on comparing the ratios a1/a2 b1/b2 and c1/c2 find out whether the pair of linear equations 2x -3y=8 and 4x-6y =9 are consistent

or inconsistent​
Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

The given linear equation are

⇒9x+3y+12=0....eq1

⇒a1 =9,b1 =3,c1 =12

⇒18x+6y+24...eq2

⇒a2 =18,b2 =6,c2 =24

⇒a1/a2 =9/18  =1/2

​⇒  b1/b2=  3/6 =  1/2

⇒  c1/c2=  12/24=  1/2

comparing

⇒  a1/a2,b1/b2,c1/c2  

⇒  a1/a2=b1/b2=c1/c2

Hence, the line represented by eq1 and eq2 are coincidents

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
two similar cylinders have surface areas of 40pi square feet and 90pi. What is the ratio of the height of the large cylinders to
Sedbober [7]
The ratio of heights  = ratio of the square roots of the areas because area is 2 dimensional and height is one dimensional.

so required ratio is  sqrt 40pi :   =  sqrt40:sqrt80 =  sqrt1: sqrt2 = sqrt (1/2) = 0.7071  to 4 significant figures 
7 0
3 years ago
Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft. 3 12 ft.3. Myla has a storage box that is 4 ft
Alex17521 [72]

Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.

Step-by-step explanation:

Formula : Volume of cuboidal box = length x width x height

width=\dfrac{Volume}{length\times height}

Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .

width=\dfrac{12}{2\times3}=2\ ft.

Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.

width=\dfrac{16}{4\times2}=2\ ft.

Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.

4 0
3 years ago
Which rule explains why these triangles are congruent? (A) ASA (B) AAS (C) SAS (D) These triangles cab not be proven congruent
DerKrebs [107]

Answer:

These triangles cannot be proven congruent.

They are similar but NOT congruent.

Step-by-step explanation:

8 0
3 years ago
Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants
lozanna [386]

Answer:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

Step-by-step explanation:

You have the following differential equation:

3y''+12y=0     (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i

The solution of the differential equation is:

y(x)=c_1e^{m_1x}+c_2e^{m_2x}   (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

4 0
3 years ago
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