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sveta [45]
3 years ago
8

The amount of algae in a bloom, P, can be modeled by the equation P = t^4 + 6t^3+ 7t^2 + 8t, where t is measured in weeks. Durin

g what interval of t will the population of algae be greater than 500?
(−∞, −6.759) ∪ (3.452, ∞)
(6.759, 3.452)
(0.3452, ∞)
(0, 3.452)

Mathematics
2 answers:
AnnyKZ [126]3 years ago
5 0

Answer:

c

Step-by-step explanation:

Mrac [35]3 years ago
5 0

Answer:

C. (0.3452, ∞)

Step-by-step explanation:

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musickatia [10]
A. 60(2/3) + 35(7/10) + 45(5/6) = $102.00

b. 60 + 35 + 45 = 140 = original price
140 - 102 = $30 saved

c. 102/140 = .7286 * 100 = 72.86 % (not sure how you need it rounded)
3 0
3 years ago
Read 2 more answers
Given uv = su tu sv prove vt = st
Lady bird [3.3K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\begin{array}{cl|cl}&\underline{\text{Statement}}&&\underline{\text{Reason}}\\1.&TU\perp SV&1.&\text{Given}\\2.&\angle TUV = 90^o&2.&\text{De finition of Perpendicular angles}\\&\angle TUS = 90^o&&\\3.&\angle TUV=\angle TUS&3.&\text{Transitive Property}\\4.&UV=US&4.&\text{Given}\\5.&TU=TU &5.&\text{Reflexive Property}\\6.&\triangle TUV = \triangle TUS&6.&\text{SAS Congruency Theorem}\\7.&VT=ST&7.&CPCTC\end{array}

5 0
3 years ago
The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th
ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

\frac{99.7\%}{2}=49.85\%

Therefore, approximately 49.85\% of lightbulb replacement requests numbering between 38 and 56.

6 0
3 years ago
A rectangular box is twice as long as it is wide. The height of the box is 3 feet less than the width. If the box is x feet wide
Xelga [282]
In order to get the volume of a rectangular box, the formula would be V = LxWxH.
So given that Length L = 2w
H = 3-w
W = x
Let x be the width, so it will look like this.
V = (2x)(x-3)(x)
Multiply these and we will get 2x^3-6x^2.
Therefore, the answer would be option D. Hope this answer helps. Let me know if you need more help next time.
8 0
3 years ago
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Help with problem 14?! 
marysya [2.9K]
All you need to know is that domain is x and range is y, like a graph.
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