2 years ago

If a line crosses the y-axis at (0, 1) and has a slope of , what is the equation of the line?

Mathematics

1 answer:

defon2 years ago

6 0

5y - 4x = 5
5y = 4x + 5
y = 4/5x + 1.....slope of 4/5 and y intercept of (0,1)

You might be interested in

Change the fraction to a decimal. a. 6⁄100 b. 43⁄100 c. 3⁄10 d. 4 23⁄1,000

g100num [7]

6/100 = 0.06

43/100 = 0.43

3/10 = 0.3

23/1,000 = 0.023

Hope this helps!

3 0

2 years ago

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/2

antiseptic1488 [7]

Y - 2 = 1/2 * ( x - 3 )
hope this helps!

5 0

2 years ago

Select all the equations that have the same solution as 3x - 12=24

USPshnik [31]

Answer:

none of the above.

Step-by-step explanation:

hope this helps you!!

8 0

2 years ago

G(r) = 25 - 31<br> g(4) =

Talja [164]

Answer:

-24

Step-by-step explanation:

25-31=-6

-6 times 4=-24

4 0

2 years ago

The arc of the parabola y = x^2 from (3,9) to (4,16) is rotated about the y-axis. Find the area of the resulting surface. Please

Hitman42 [59]

Answer:

156.5

Step-by-step explanation:

Thinking process:

The area can be calculated using the formula:

$S = \int\limits^4_3 {2\pi x\sqrt{1+}(2x)^{2} } \, dx$

We let the substitution take place.

Therefore, we let $u = 1 + 4x^{2}$

Thus, $du = 8dx.$

So,

$xdx = \frac{1}{8}du$

Also, the interval of the integration changes to [ 37, 65]

Thus,

$S = \int\limits^4_3 {2\pi \sqrt{1+4x^{2} } } \, dx \\= \int\limits^65_35 {2\pi \sqrt{\frac{1}{8}u } } \, dx$

= $\frac{1}{6} [ 65^{\frac{3}{2}-37^{\frac{3}{2} } }$

= 156.5 units²

8 0

2 years ago