Hey there!

The shape being described in letter A is a prism. A prism has two polygonal shapes on either end that can be any shape consisting of three or more sides. This won't be your answer, since cylinders have circular bases on either side.

The shape being described in letter B is a cylinder. Not sure why they needed to throw in the plane part, but this is the only answer that describes the bases as being circular (or, as they put it, discs).

The shape being described in letter C is a pyramid. If a shape has a polygonal base and meets at a point at the other end, it will be a pyramid. Obviously, a pyramid only has one end, meaning that this isn't your answer.

The shape being described in letter D is a cone. Again, if a shape has a base and meets at a point, it will be a pyramid. However, in the case of a cone, the base will be circular and the other side will meet at a point. The entire shape will be rounded where a pyramid would have edges. Again, not your answer.

Your answer will be B. Hope this helped you out! :-)

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3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$