Kenya jumped 7 and 1 sixth feet. Janet jumped 6 and 1 third feet. How much farther did Kenya jump?

Joe owes his sister Lisa $12 and his sister kelly $18 his brother David owes joe $20. Joe writes the number -12 to represent the

Luda [366]

Got confused on the part of kelly...

7 0

3 years ago

Read 2 more answers

The owner of the Good Deals Store opens a newstore across town. For the new store, the ownerestimates that, during business hour

mestny [16]

60 % less customers than the typical customer count in the original store at any given time.

The correct option is A.

<h3>What is Average number?</h3>

The total number of values in a given set divided by the sum of all the values is how an average is calculated. The arithmetic mean is another name for it. To get the average, let's look at some basic facts. The available values are 1, 2, 3, 4, and 5. Average is the total sum of all values or the total number of values.

<h3>According to the given information:</h3>

At any given time, the original business had an estimated average of 45 customers. According to the manager of the new store, on average 90 customers each hour—or 1.5 customers per minute—enter the establishment.

Additionally, the manager calculates that each customer spends an average of 12 minutes inside the shop.

According to Little's law, the new business has customers inside on average at all times.

, N=rt=(1.5)(12)=18

So,

= ((45−18)/45) ×100

=60

60 % less customers than the typical customer count in the original store at any given time

To know more about Average number visit:

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I understand that the question you are looking for is:

The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time?

A.60

B.70

C.80

D.50

6 0

2 years ago

A 90% confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a

Stella [2.4K]

Answer:

b) We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $139,048 to $154,144.

Step-by-step explanation:

Confidence interval:

Confidence level of x%

We build from a sample.

Between a and b.

Intepretation: We are x% sure that the population mean is between a and b.

In this question:

90%

45 CEO's

Between ($139,048, $154,144).

So

We are 90% sure that the mean salary of all CEO's falls within this interval.

The correct answer is:

b) We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $139,048 to $154,144.

4 0

3 years ago

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$