Convert the measurement as indicated. <br> 91qt=_gal

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

Use the discriminant to determine the number of real solutions for the equation below.

Murljashka [212]

Answer:

there is one real solution

Step-by-step explanation:

use the quadratic formula. what is in the square root is called the discriminant.

since it came out to 0 there is one real solution

5 0

4 years ago

The cost per month is a good way to compare different modes of transportation.

Nat2105 [25]

The answer is A. True hope this right

5 0

3 years ago

Read 2 more answers

Select the point that is a solution to the system of inequalities

ExtremeBDS [4]

<h3>Answer: B. (-1, 0)</h3>

This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.

In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality $y \le x^2-3x$ true. So this is why we can rule choice A out.

Choice C is not a solution because (4,1) does not make $y \le -x+3$ true. This point is not below the red diagonal line. We can cross choice C off the list.

Choice D is similar to choice A, which is why we can rule it out as well.

5 0

3 years ago

How many ways can one rearrange the letters in the word circumference to form a string of 13 letter strings or words sensible or

Varvara68 [4.7K]

25 i think, i just used an anagram server to generate it

4 0

3 years ago

Convert the measurement as indicated. 91qt=_gal_qt