Given: Quadrilateral ABCD is a parallelogram with diagonals AC and BD intersecting at E. Prove: Triangle AED is congruent to Tri
angle CEB
1 answer:
Answer:
Step-by-step explanation:
In ΔAED , ΔCEB
AD = BC { opposite sides of parallelogram are equal}
AE = CE { diagonals of parallelogram bisects each other}
BE = DE { diagonals of parallelogram bisects each other}
ΔAED ≅ ΔCEB (SSS congruence)
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