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Rus_ich [418]
3 years ago
7

A right triangle has legs of lengths 14 and 16 inches. Find the length of

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

about 21.3

Step-by-step explanation:

I found the hypotenuse value by doing the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs, and "c" is the value of the hypotenuse. So, "a" is 14 and "b" is 16.

14^2+16^2=c^2

196+256=452.

Now, I found the square root of 452. The square root of 452 is 21.26029163. This value rounded to the nearest tenth is 21.3.

In conclusion, the length of the hypotenuse rounded to the nearest tenth is 21.3 inches.

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adoni [48]
6/8+7/8=13/8 or 1 5/8
4 0
3 years ago
A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d
nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

P(t)=Ce^{kt}

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

P(t)=Ce^{kt}

For t=0, we have:

P(0)=Ce^0=C=58

If we use the duplication time, we have:

P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08

Then, we have the model as:

P(t)=58e^{2.08t}

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644

The rate of growth can be calculated as dP/dt and is:

dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)

For t=8, the rate of growth is:

dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81

3 0
3 years ago
10 oranges cost Php 120 ,how much 35 oranges cost?​
ValentinkaMS [17]
I believe the answer is 420
4 0
3 years ago
Read 2 more answers
Write an equation based on these world problemKelsie wants to go play airsoft for $18.99 each hour (let that be h for hours) + $
Strike441 [17]

Solution

Problem 1:

- Kelsie pays a one-time fee for the equipment of $5.00. This is a fixed cost that never changes and is paid just once.

- Kelsie pays $18.99 for each hour (h). This means that

For 1 hour, Kelsie pays $18.99 * 1 = $18.99

For 2 hours, Kelsie pays $18.99 * 2

For 3 hours, Kelsie pays $18.99 * 3

And so on...

- We can generalize this for h hours. That is,

For h hours, Kelsie pays $18.99 * h

- Thus, Kelsie pays $18.99h after h hours separate from the initial fee of $5.00.

- Thus, her total cost would be the addition of the flat fee of $5.00 and the cost of playing for h hours. That is:

\begin{gathered} Total\text{ Cost}(A)=18.99h+5 \\ where, \\ h=\text{ Number of hours elapsed} \end{gathered}

Problem 2:

- Jayson pays $35 per hour with no initial flat fee.

- Following the same logic as in the case of Kelsie, we can write the total cost incurred by Jayson after h hours is:

Total\text{ Cost\lparen P\rparen}=35h

Final Answer

The answers are:

Problem 1:

A=18.99h+5

Problem 2:

P=35h

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9 months ago
Which statement best describes the relationship shown in the table?
yuradex [85]
As input increased by 1, output triples
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2 years ago
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