1. y<span> ≤ 4x/3+5
2. y</span><span>< 6x/4+3</span>
Answer:
π/8 radians
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION
In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?
SOLUTION
✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.
Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)
Within the 1hour minutes, the hand can move with complete cycle of 2π radians
Then At time t= 45minutes
Angle through the circle at 45 minutes= 45/60 ×2π radians
= 3π/2 radians
And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians
For t=45 minutes
Then 1/12 × 2π ×45/60
= π/8 radians
Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.
Answer:
In a pair of similar triangles, the corresponding sides are proportional.
Step-by-step explanation:
Corresponding sides touch the same two angle pairs. When the sides are corresponding it means to go from one triangle to another you can multiply each side by the same number.
Vcylinder=hpir^2
Vcone=(1/3)hpir^2
d/2=r
so
1.
d=8
r=8/2=4
h=3r
h=3(4)
h=12
V=12*3.14*4^2
V=602.88 in^2
2. cone that fits has same base area and therefor same radius
d=6
r=6/2=3
rcone=3
find height of can
V=hpir^2
21=h*3.14*3^2
21=h*3.14*9
0.7431=h
so
cone height=0.7431
radius=3
V=(1/3)(0.7431)(3.14)(3^2)
V=7 cubic units
3.
same base
find dimentions
s=s=s
V=s^3
27=s^2
3=s
Vsquarepyramid=(1/3)hs^2
s=legnth of base
h=height
h=side
V=(1/3)(3)(3^2)
V=9
C
1. 602.88 in^2
2. 7 cubic units
3. 9cm^3, C