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Yuki888 [10]
3 years ago
6

HELP ME PLEASE WITH THIS

Mathematics
1 answer:
solniwko [45]3 years ago
8 0
Correct Answer: 65 degrees Fahrenheit
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. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the
inn [45]

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

\frac{210}{x + 2}  =  \frac{150}{x}

X represents the speed of the second car. By cross multiplying, you get the following equation:

210x = 150(x + 20)

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.

4 0
2 years ago
Please someone help me in this
Elis [28]

Answer:

20 watches were made.

Step-by-step explanation:

385=15n+85

300=15n

20=n

7 0
3 years ago
Read 2 more answers
Which is greater 0.01 or 0.6??
AysviL [449]

i am pretty sure it is 0.6

8 0
3 years ago
Read 2 more answers
2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16
Masja [62]

Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}

With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

8 0
3 years ago
A certain organization recommends the use of passwords with the following​ format: vowel commavowel, consonant comma consonant c
zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices  are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

5\times21\times21\times21\times5\times21\times10\times10

= 486202500

Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

10\times42\times42\times42\times10\times42\times10\times10

= 31116960000

4 0
3 years ago
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