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DaniilM [7]
3 years ago
5

Need the answer plzz

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

20 \times 11.5 + 20 \times 11.75 + 20 \times 11.5 + 20 \times 11.75 + 2 \times (11.75 \times 11.5) \\  = 1200.25 {in}^{2}

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Carly mowed 2 more lawns than Rocco each week for 6 weeks. Carley mowed a total of 18 lawns. How many lawns did Rocco mow each w
Reptile [31]
Rocco mowed 1 lawn a week.

You wanna divide Carley’s total mowed lawns by the amount of weeks she mowed for.
18/6 = 3
Carley mowed 3 lawns a week.
We’ll take away two from that because she mowed two more that Rocco each week, resulting in Rocco mowing one lawn a week.
Hope this helps!! :))
8 0
3 years ago
6.493 rounded to the hundredths
Nana76 [90]
The answer is 6. 49 you welcome :)
7 0
3 years ago
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Simplify -2+3(1-4)-2​
oksian1 [2.3K]

Answer:

-13

Step-by-step explanation:

−2+3(1−4)−2

=−2+(3)(−3)−2

=−2+−9−2

=−11−2

=−13

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4 0
3 years ago
A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.
Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

3 0
3 years ago
Read 2 more answers
What is the domain of the function shown in the graph below?
Maksim231197 [3]

Answer:

Domain: (+∞, -∞)

Step-by-step explanation:

Domain = x value

hope it helps

6 0
3 years ago
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