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Alex_Xolod [135]
3 years ago
8

demand for a particular type of battery fluctuates from one week to the the next. A study of the last six weeks provides the fol

lowing demands (in dozens): 5, 5, 3, 2, 8, 10 (last week). forecast demand for next week using a three-week moving average where the weights are 3, 2, 1, (the heighest weight is for the most recent number).
Business
2 answers:
Dmitriy789 [7]3 years ago
7 0
Given the weighted we have and the requirement is to use the three-week moving average, we come up with the sales forecast by applying the formula as shown below:
(3x1 + 2x2 + 3x3) / 6 = 2.67
Sedaia [141]3 years ago
6 0

Answer:

16

Explanation:

Given:

Demands = 5, 5, 3, 2, 8, 10

now,

since the highest weight is for the most recent number , Weights assigned will be

Demand    weight

10                3

8                 2

2                 1

Therefore,

Forecast demand = \frac{\sum{Weight\times Demand}}{3}

or

Forecast demand = \frac{3\times10+2\times8+1\times2}}{3}

or

Forecast demand = 16

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2 years ago
A small market orders copies of a certain magazine for its magazine rack each week. Let X 5 demand for the magazine, with pmf Su
Oksanka [162]

Answer:

See explanation below.

Explanation:

Let X the random variable that represent the demand for the magazine, the pmf for X is given by:

X       1            2           3          4        5        6      

P(X)  1/15      2/15       3/15     4/15   3/15     2/15

3 magazines

For this case the total spent is 2*3 = $ 6

And the net revenue for this case would be:

$4-$6 = -$2 , X=1 (demand 1)

$4*2-$6 = $2 , X=2 (demand 2)

$4*3-$6 = $6 , X=3 (demand 3)

For the values of X=4,5,6 the net revenue will be $6 since the number of magazines is 3

And the expected value for the net revenue would be:

E(R) = \frac{1}{15} *(-2) +\frac{2}{15} *(2) +\frac{3}{15}*(6) + \frac{4}{15}*(6) +\frac{3}{15}*(6) +\frac{2}{15}*(6) = \frac{74}{15}=4.93

4 magazines

For this case the total spent is 2*4 = $ 8

And the net revenue for this case would be:

$4-$8 = -$4 , X=1 (demand 1)

$4*2-$8 = $0 , X=2 (demand 2)

$4*3-$8 = $4 , X=3 (demand 3)

$4*4-$8 = $8 , X=4 (demand 4)

For the values of X=5,6 the net revenue will be $8 since the number of magazines is 4

And the expected value for the net revenue would be:

E(R) = \frac{1}{15} *(-4) +\frac{2}{15} *(0) +\frac{3}{15}*(4) + \frac{4}{15}*(8) +\frac{3}{15}*(8) +\frac{2}{15}*(8) = \frac{80}{15}=5.33

As as we can see we have a higher expected value for the case with 4 magazines.

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Read 2 more answers
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