How many two-digit primes have both their digits non-prime? 6 5 4 3 2

Une machine sert à fabriquer tous les triangles rectangles (uniques en termes de proportions) dont les côtés ont pour

aliina [53]

Answer:

............

Step-by-step explanation:

..

.

..........

4 0

3 years ago

The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If

Molodets [167]

Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

$p=1-e^{-mt}$

You know that:

The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

$m=6$

As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:

$t=0.5$

Substitute the values above into the formula.

Then, you obtain:

$p=1-e^{-(6)(0.5)}=0.95$ or 95%

7 0

2 years ago

Jane has $5 more than three times as much money as Lonnie has.Bob has $1 less than four times as much money as Lonnie has. All t

kkurt [141]

Starting equation:
92=J+L+B

To find how much money Jane has, we use the equation:
J=5+3L
To find how much money Bob has, we use the equation:
B=4L-1

Enter those equations in the problem

92=(5+3L)+L+(4L-1)
Combine like terms
92=4+8L
Subtract 4 to isolate variable
88=8L
Divide by 8 to isolate variable
11=L

Answer:
Lonnie has $11
Jane has $38
Bob has $43

side note: Lonnie is that one poor friend we all have

5 0

3 years ago

The data given below contain the state cigarette taxâ€‹ (in $) for all 20 regions of a country.

g100num [7]

Answer:

(a) $\bar x= 1.583$ -- Population Mean

(b) $s = 1.032$ --- Population standard deviation

(c) See Explanation

Step-by-step explanation:

Given:

Cigarette tax for 20 regions

Solving (a): The population mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

$\sum x = 1.36 + 1.70 + 2.50 + 0.45 + 1.18 + 0.64 + 3.46 + 0.57 + 2.00 + 0.80 + 1.60 +0.98 + 0.36 + 2.24 + 4.35 + 0.62 + 2.70 + 1.78 + 1.53 + 0.84$

$\sum x = 31.66$

$n = 20$

So, we have:

$\bar x= \frac{31.66}{20}$

$\bar x= 1.583$

Solving (b): The population standard deviation

This is calculated as:

$s = \sqrt{\frac{\sum( x - \bar x)^2}{n}$

$\sum (x -\bar x)^2 = (1.36 - 1.583)^2 + (1.70 - 1.583)^2+ (2.50 - 1.583)^2+ (0.45 - 1.583)^2+ (1.18 - 1.583)^2+ (0.64 - 1.583)^2+ (3.46 - 1.583)^2+ (0.57 - 1.583)^2+ (2.00 - 1.583)^2+ (0.80 - 1.583)^2+ (1.60 - 1.583)^2+(0.98 - 1.583)^2+ (0.36 - 1.583)^2+ (2.24 - 1.583)^2+ (4.35 - 1.583)^2+ (0.62 - 1.583)^2+ (2.70 - 1.583)^2+ (1.78 - 1.583)^2+ (1.53 - 1.583)^2+ (0.84- 1.583)^2$