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3 years ago

Find the measure for each angle

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

A/B - 90° | C - 42° | D - 48 | E - 132

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X^2-12x+36=0

kari74 [83]

This expression is a perfect square trinomial. It has two answers but they don't have to be different. In this case it has to be the same - because it is a perfect square trinomial.

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3 years ago

Read 2 more answers

-8 equals x + 11 / -2

slava [35]

If the equation is $-8=x+\frac{11}{-2}$ :

$-8=x+\frac{11}{-2}\\-8=x-\frac{11}{2}\\-8+\frac{11}{2}=x-\frac{11}{2}+\frac{11}{2}\\-\frac{16}{2}+\frac{11}{2}=x\\x=-\frac{5}{2}=-2\frac{1}{2}$

If the equation is $-8=\frac{x+11}{-2}$ :

$-8=\frac{x+11}{-2}\\-8(-2)=\frac{x+11}{-2}(-2)\\16=\frac{-2(x+11)}{-2}\\16=x+11\\16-11=x+11-11\\x=5$

Hopefully the math was self-explanatory. If it is not, please feel free to ask for a step-by-step, in depth explanation, and I will edit my answer to accommodate.

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3 years ago

An amount of $18,000 is borrowed for 10 years at 8.25% interest, compounded annually. If the loan is paid in full at the end of

cricket20 [7]

218 dollars will have to be paid back

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}$

$0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}$

$\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}$

$n = 382.23$

Rounding up

We need a sample size of at least 383.

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3 years ago

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 7 − x 2 y=7-x2. what are the dime

slega [8]

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 7 − x 2 y=7-x2. what are the dimensions of such a rectangle with the greatest possible area?

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4 years ago