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1 year ago

Company A: $39.99 per month no installation fee

Mathematics

1 answer:

Svetlanka [38]1 year ago

6 0

Company A represents a proportional relationship, while company B does not.

<h3>Proportional relationship</h3>

The general format of a equation representing a proportional relationship is given as follows:

y = rx.

A proportional relationship is a special case of a linear function, having an intercept of zero.

Then, the output variable y is calculated as the multiplication of the input variable x by the constant of proportionality k.

The costs for each company after x months, in this problem, are represented as follows:

A(x) = 39.99x.

B(x) = 34.99x + 50.

Company B has an intercept different of zero, hence it is not a proportional relationship, while Company A, with an intercept of zero, represents a proportional relationship.

<h3>Missing Information</h3>

The complete problem is:

Two companies offer digital cable television as described below.

Company A: $39.99 per month no installation fee

Company B: $34.99 per month with a $50 installation fee

For each company tell whether the relationship is proportional between months of service and total cost is a proportional relationship. Explain why or why not

More can be learned about proportional relationships at brainly.com/question/10424180

#SPJ1

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What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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3 years ago

A math teacher who likes baseball conducts a survey of 100 students. He asked the students about their favorite sport and about

galben [10]

Answer:

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Step-by-step explanation:

see image attached!

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3 years ago

Which is greater 1/10 or .09 why?

lesantik [10]

Answer:

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Step-by-step explanation:

Decimal Form:

0.09

0.1

Fraction Form:

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1/10

Percentage Form:

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2 years ago

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jolli1 [7]

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3 years ago

Check answer please

Cerrena [4.2K]

The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

$\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}$

$\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}$

$\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}$

$\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}$

Hope it helps.

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3 years ago