Answer:
d67d6d 34r2
Step-by-step explanation:
d53eududc6ttd5cf
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Answer:
This cannot be solved but it can be simplified
first we open the bracket
so we have
a²- abx/x = 2/3
next we cross multiply so it will be 3(a² - abx) = 2x
we get
3a² - 3abx = 2x
Next we factorise so we can get
3a(a-bx) =2x
I dont know what exactly you where asked but I hop this helps
Answer:
D.The distance you drive
Step-by-step explanation:
If you describe this situation as function, then it will look as:
- f(h)= 60h
- For h=1 you have f(1)= 60 miles
- For h=2 you have f(2)= 120 miles etc.
The range of the function is the set of output values
In this case the range is the distance you drive
Correct option is D.
Answer:
(f + g)(x) = 12x² + 16x + 9 ⇒ 3rd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- We can add and subtract two function by adding and subtracting their
like terms
Ex: If f(x) = 2x + 3 and g(x) = 5 - 7x, then
(f + g)(x) = 2x + 3 + 5 - 7x = 8 - 5x
(f - g)(x) = 2x + 3 - (5 - 7x) = 2x + 3 - 5 + 7x = 9x - 2
* Lets solve the problem
∵ f(x) = 12x² + 7x + 2
∵ g(x) = 9x + 7
- To find (f + g)(x) add their like terms
∴ (f + g)(x) = (12x² + 7x + 2) + (9x + 7)
∵ 7x and 9x are like terms
∵ 2 and 7 are like terms
∴ (f + g)(x) = 12x² + (7x + 9x) + (2 + 7)
∴ (f + g)(x) = 12x² + 16x + 9
* (f + g)(x) = 12x² + 16x + 9
