All categories

3 years ago

I need some help! i will try to give brainliest!!!

Mathematics

1 answer:

o-na [289]3 years ago

7 0

Answer:

its A because the Y intercept is at 3

You might be interested in

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0

3 years ago

I really need help on my geometry homework!!!!! PLEASE HELP ME!!!!

otez555 [7]

the 10th questions answer is aaa congruence

3 0

3 years ago

Help with this question plz I need the answer plz help me plz

olga nikolaevna [1]

Answer:

Step-by-step explanation:

45:15=3:1 not 1:3

4 0

3 years ago

Read 2 more answers

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

3 0

2 years ago

Geometry help greatly needed. please help if possible.

elixir [45]

Answer:

$\huge\boxed{\sf x = 90\°}$

Step-by-step explanation:

If AB is diameter, the angle opposite to it, when a triangle is inscribed in that semi circle, will be 90 degrees.

<u>Given that:</u>

AB is the diameter.

According to what is given, we come to know that <ACB = x = 90°.

$\rule[225]{225}{2}$

Hope this helped!

3 0

3 years ago