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coldgirl [10]
3 years ago
15

The nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports

that the wind is coming from the west at 69 miles per hour. in order to travel in a straight line, the ring wraiths decide to head northwest. at what speed should they fly (omit units)?
Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Velocity of the ring wraiths relative to the air:

\vec v_{W/A}=(v_{W/A}\cos45^\circ,v_{W/A}\sin45^\circ)=\left(\dfrac{v_{W/A}}{\sqrt2},\dfrac{v_{W/A}}{\sqrt2}\right)

The speed v_{W/A} is what we want to find - this is the speed at which the wraiths are flying in the air.

(Note: \vec v denotes velocity, while v denotes speed)

Velocity of air relative to the ground:

\vec v_{A/G}=((69\,\mathrm{mph})\cos180^\circ,(69\,\mathrm{mph})\sin180^\circ)=(-69,0)\,\mathrm{mph}

The ring wraiths want their trajectory to be due north, which means their velocity relative to the ground should be

\vec v_{W/G}=(v_{W/G}\cos90^\circ,v_{W/G}\sin90^\circ)=(0,v_{W/G})

To an observer on the ground, v_{W/G} is the speed at which the wraiths would appear to be moving in the air.

The relative velocities satisify

\vec v_{W/A}+\vec v_{A/G}=\vec v_{W/G}

\implies\begin{cases}\dfrac{v_{W/A}}{\sqrt2}-(69\,\mathrm{mph})=0\\\\\dfrac{v_{W/A}}{\sqrt2}=v_{W/G}\end{cases}

\implies v_{W/A}=69\sqrt2\,\mathrm{mph}\approx98\,\mathrm{mph}

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