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Elza [17]
3 years ago
11

Can someone please answer this asap (50 Points) Graph the following piecewise function.

Mathematics
2 answers:
kiruha [24]3 years ago
8 0

answer D for the equation

Brums [2.3K]3 years ago
4 0

The solution is in the image

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Question in the image
dalvyx [7]
The exact surface area is 150.8 and the exact volume is 141.37.

To answer this I used the formula for surface are for a right cylinder which is. 2•3.14•r•h+2•3.14•r^2 (^2 means to the power of 2) r=radius and h=height. When you replace the r’s and the h’s with the radius and height it’ll look like this. 2•3.14•3•5+2•3.14•3^2. For the power of 2 (^2) we basically just do 3•3. But when you put that into a calculator it gives you 150.8.

To find the volume use the formula 3.14•r^2•h when you replace the r’s and the h’s with the height and the radius it’ll look like this. 3.14•3^2•5. When put into the calculator it gives you 141.37.
7 0
2 years ago
Which statement about the slope of a line is true?
Fudgin [204]

Answer:

B) A line with a positive slope increases as it is viewed from left to right.

Step-by-step explanation:

A line with a positive slope increases as it is viewed from left to right.

A positive slope means that as a line on the line graph moves from left to right, the line rises.

Hope this helps :)

8 0
2 years ago
I need to show work real answers plz
Paul [167]
X= -2 and y = -6. Here is the work
6 0
2 years ago
Read 2 more answers
Help me ;-;<br><br> Find (2)(‐3)
aliina [53]
-6
Would be your answer
8 0
2 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
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