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liraira [26]
3 years ago
8

Which of the following equations have exactly one solution? Choose all answers that apply: A:58x+52=78x−78 B:−78x+52=−52x−78 C:5

2x+52=52x−78 D:58x+52=−78x−78
Mathematics
2 answers:
Reil [10]3 years ago
8 0

For this case we solve each of the equations:

Option A:

58x+52=78x-78\\58x-78x= -78-52\\-20x = -130

x = \frac {-130} {- 20}\\x = \frac {13} {2}

It has a solution!

Option B:

-78x + 52 =-52x-78\\-78x + 52x=-78-52\\-26x = -130

x=\frac{-130}{-26}\\\\x=5

It has a solution!

Option C:

52x + 52=52x-78\\52x-52 = -78-52\\0 = -130

The equation has no solution!

Option D:

58x + 52=-78x-78\\58x + 78x = -78-52\\136x = -130

x = - \frac{130} {136}\\x = - \frac{65} {68}

It has a solution!

Answer:

Option A, B, D

irga5000 [103]3 years ago
5 0

Answer:

A,B,C

Step-by-step explanation:

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Help with algebra 2 I can’t figure out how to solve the problem .
defon

Answer: D

Step-by-step explanation:

Using the equation plot in the coordinates of the points to see if they fit the equation.

5x-3y < 30  

A)  5(-3) -3(5) < 30

   -15 -15 < 30

    -30 < 30   This is true

B)  5(0) -3(0) < 30

     0 - 0 < 30

     0< 30     This is true

C)  5(-5) - 3(3) < 30

    -25 - 9  < 30

      -34 < 30    This is also true

D) 5(3) - 3(-5) < 30  

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3 years ago
A team of 17 softball players need to choose three players to refill the water cooler. How many different ways are there to sele
KATRIN_1 [288]
<h3>Answer: 680 different combinations</h3>

=======================================================

Explanation:

If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.

So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.

An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

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