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3 years ago

Whats the property shown for this problem? ||Associative||Commutative||Opposite||

Mathematics

2 answers:

anzhelika [568]3 years ago

7 0

I would go with associative property.

Allisa [31]3 years ago

4 0

It would be Associative because since you are keeping the same numbers only changing the " ( ) ".

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Find an equation of the circle whose diameter has endpoints (1,-4) and (-3,6).

MAVERICK [17]

Answer:

$(x+1)^2+(y-1)^2=58$

Step-by-step explanation:

To find the equation of this circle, we must know the center and the radius.

We can find the radius by dividing the value of the distance formula by 2 (since $r=\frac{d}{2}$ ):

$d=\sqrt{(-3-1)^2+(6-(-4))^2}=\sqrt{116}\\r=d/2=\frac{\sqrt{116}}{2}$

We can then find the center of the circle by averaging the coordinates:

$\frac{1+(-3)}{2}=-1$

$\frac{-4+6}{2}=1$

Then, we substitute these values into the equation of a circle:

$(x-(-1))^2+(y-1)^2=(\frac{\sqrt{116}}{2})^2\\(x+1)^2+(y-1)^2=58$

3 0

4 years ago

Extra points giving away who ever get this right first gets brainlest 468 weeks = ______ years

Colt1911 [192]

8yrs
8.975
hope that helps

8 0

3 years ago

Which correctly describes the graph shown below

Alborosie

The answer is C. Explanation: The line isn’t a straight line, so it can’t be a linear line. Then, do the vertical line test to see if the line is a function (to do this, draw a vertical line through the graph, and see if it passes more than one point on the graph. If the vertical line passes any more than one point on the graph on any spot, it is not a function), and since the graph fails the vertical line test, it is not a function. Therefore, the answer is C.

5 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl

Eva8 [605]

Substitute $u=\ln x$ , so that $\mathrm du=\dfrac{\mathrm dx}x$ . The integral is then equivalent to

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}$

Then transforming back to $x$ gives

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}$

4 0

3 years ago

36. How many 13 -card hands dealt from a standard deck will have exactly seven spades?

barxatty [35]

Answer:

id k give a second

Step-by-step explanation:

7 0

2 years ago